Cattle coat color is determined by codominant alleles R and r. RR results in a reddish cow

1. Cattle coat color is determined by codominant alleles R and r. RR results in a reddish cow, Rrin a roan coloured cow, and rr in a white coloured cow. A population of 4000 cattle consisted of2560 reds, 1280 roans and 160 white cattle. Calculate the gene frequency of the ‘R’ gene and the’r’ gene. If you fill in the Table below you’ll have your answer:PhenotypeNumber of cattle160Totalr0r1280WhiteR2560RoanGene FrequencyRRedNumber of genes0400000Hence the overall gene frequency (f(p)) of the red gene =Hence the overall gene frequency (f(q)) of the white gene =You can also solve this question using the Hardy Weinberg formula2. PKU (phenylketonuria) occurs in about 1 out of 12,000 Caucasians. It is rarer in other ethnicgroups. Calculate the frequency of the recessive disease causing gene. Calculate the frequencyof the normal gene. Complete the following table:Human PhenotypesNumber in a population of 12000NormalHumanGenotypesNumber in a population of 1200015624NormalCarrierShowing PKU1ShowingPKU1Hint: Here you must start the answer by calculating the frequency of the homozygousrecessive gene q and you know that homozygous individuals occur in the population onceevery 12,000 individuals. Hence q2 = 1 in 15625.3. 10% of human males in a sampled population were found to be red/green colorblind. This is arecessive sex-linked condition. What proportion of human females are expected to be colorblindin this population. Hint: You might find it easier to answer this question if you referred to the tablebelow, where Xb is the recessive X-linked colour-blind allele and XB is the dominant normal gene.SexCategoryHomozygousHeterozygousHomozygousDominantRecessiveGenotypeXB XBXB XbXb XbPhenotypeFEMALESDominantnormalnormalcolour-blindXBXB and XbXbGenotypeXB YDOESXb YPhenotypenormalNOTcolour-blindGamete TypesMALES(Percentage)(Then you can fillthis in)Gamete TypesXB and Y(First you must fillthis in)EXISTXb and Y